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At 1000C and 1 atm, if the density of the liquid water is 1.0 g cm−3 and that of water vapour is 0.0006 g cm−3, then the volume occupied by water molecules in 1 L of steam at this temperature is

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answer is 3.

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Detailed Solution

For water vapour, P=0.0006 g cc−1∴ 0.0006=MassVolume=Mass1000Mass = 1000 × 0.0006=0.6 gThe density of liquid water is 1 g cc−1So, the volume occupied by water is MassDensity=0.61=0.6 cc

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