$$CH33COH+CH3MgBr$$→ Hydrocarbon (A). A $$is____$$

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Question

${(C H_{3})}_{3} C O H + C H_{3} M g B r \underset{}{\to}$ Hydrocarbon (A). A is____

Solution

$R M g X \frac{A c t i v e (H)}{o r H^{+}} R H$ , this is the common reaction, hence the reaction is $C H_{3} M g B r \to_{}^{{(C H_{3})}_{3} C O - H} C H_{4}$

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