C6H5CH2Br→etherMgA→ CdCl2B→ CH3COClC . Incorrect statement is

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B is C6H5CH22Cd

C is C6H5CH2COCH3

C→ NaBH4C6H5CH2CH2CH3

‘C’ is a metamer of ethyl phenyl ketone

answer is C.

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Detailed Solution

B is C6H5CH22CdC6H5CH22Cd+2CH3COCl→ 2C6H5CH2COCH3 C+CdCl2 C6H5CH2COCH3 and C6H5COCH2C6H5 are metamersC6H5CH2COCH3→ NaBH4C6H5CH2CHOHCH3

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