C6H5−CH=CHCHO→XC6H5CH=CHCH2OH. In the above sequence X can be

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H2/Ni

K2Cr2O7/H+

NaBH4

Both (1) and (3)

answer is C.

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Detailed Solution

NaBH4 and LiAH4 attack only carbonyl group and reduce it into alcohol group. They do not attack on double bond.C6H5−CH=CHCHOcinnamic aldehyde→NaBH4C6H5−CH=CH.CH2OHcinnamic alcoholWhereas H2/Ni affects double bond and K2Cr2O7/H+ carries oxidation.

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