Q.

C6H5CNA→ SnCl2+HClB→ H3O+C.  Incorrect statement is

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a

A is Benzonitrile (or) Benzene carbonitrile

b

B is benzene amine

c

Functional group in ‘C’ is deactivating, m – directing group

d

C6H5CHO→ΔNH3B

answer is B.

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Detailed Solution

C6H5−C≡NA→ SnCl2+HClC6H5−CH=NHB→ H3O+C6H5CHO+NH3C‘B’ is Benzaldimine– CHO  group is m – directing and deactivating towards ESRC6H5−CH=O+H2NH→ ΔC6H5−CH=NHB
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