C6H5CNA→ SnCl2+HClB→ H3O+C. Incorrect statement is
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a
A is Benzonitrile (or) Benzene carbonitrile
b
B is benzene amine
c
Functional group in ‘C’ is deactivating, m – directing group
d
C6H5CHO→ΔNH3B
answer is B.
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Detailed Solution
C6H5−C≡NA→ SnCl2+HClC6H5−CH=NHB→ H3O+C6H5CHO+NH3C‘B’ is Benzaldimine– CHO group is m – directing and deactivating towards ESRC6H5−CH=O+H2NH→ ΔC6H5−CH=NHB