Q.
C4H10OA →KMnO4 / H+ C4H8O2.‘A’ when treated with PCl3 followed by reduction with Zn / HCl gives n – butane. ‘A’ is
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a
n-butyl alcohol
b
20 butyl alcohol
c
Isobutyl alcohol
d
30 butyl alcohol
answer is A.
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Detailed Solution
On Strong OxidationAll compounds contain same number of carbon atoms∴ ‘A’ can be (1) (or) (3) If A is option (3)So ‘A’ cannot be (3)CH3CH2CH2CH2OH→PCl3 CH3CH2CH2CH2Cl→ Zn/HClCH3CH2CH2CH3n−butane
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