Q.

C4H10OA →KMnO4 /  H+  C4H8O2.‘A’ when treated with PCl3 followed by reduction with Zn / HCl gives n – butane. ‘A’ is

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By Expert Faculty of Sri Chaitanya

a

n-butyl alcohol

b

20 butyl alcohol

c

Isobutyl alcohol

d

30 butyl alcohol

answer is 1.

(Detailed Solution Below)

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Detailed Solution

On Strong OxidationAll compounds contain same number of carbon atoms∴  ‘A’ can be (1) (or) (3)      If A is option (3)So ‘A’ cannot be (3)CH3CH2CH2CH2OH→PCl3 CH3CH2CH2CH2Cl→ Zn/HClCH3CH2CH2CH3n−butane
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