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C4H10OAKMnO4/  H+  C4H8O2.A when treated with PCl3 followed by reduction with Zn / HCl gives n  butane. A is

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By Expert Faculty of Sri Chaitanya
a
n-butyl alcohol
b
20 butyl alcohol
c
Isobutyl alcohol
d
30 butyl alcohol
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detailed solution

Correct option is A

On Strong OxidationAll compounds contain same number of carbon atoms∴  ‘A’ can be (1) (or) (3)      If A is option (3)So ‘A’ cannot be (3)CH3CH2CH2CH2OH→PCl3 CH3CH2CH2CH2Cl→ Zn/HClCH3CH2CH2CH3n−butane


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