C4H10OA →KMnO4 / H+ C4H8O2.‘A’ when treated with PCl3 followed by reduction with Zn / HCl gives n – butane. ‘A’ is
n-butyl alcohol
20 butyl alcohol
Isobutyl alcohol
30 butyl alcohol
On Strong Oxidation
All compounds contain same number of carbon atoms
∴ ‘A’ can be (1) (or) (3)
If A is option (3)
So ‘A’ cannot be (3)
CH3CH2CH2CH2OH→PCl3 CH3CH2CH2CH2Cl→ Zn/HClCH3CH2CH2CH3n−butane