At 25°C and 760 mm of Hg pressure a gas occupies 600 mL volume. What will be its pressure at a height where temperature is 10°C and volume of the gas is 640 mL?

p1=760 mmHg,V1=600 mL,T1=25+273=298 KV2=640 mL and T2=10+273=283 KAccording to combined gas law,p1V1T1=p2V2T2⇒   p2=p1V1T2T1V2⇒  p2=(760 mmHg)×(600 mL)×(283 K)(640 mL)×(298 K)= 676.6 mmHg ≈ 677 mmHg