First slide

Conductivity , Molar conductivity and Equivalent Conductivity

Question

At 25⁰C the molar conductances at infinite dilution for the strong electrolytes NaOH, NaCl and BaCl₂ are 248 × 10^–4, 126 × 10^–4 and 280 × 10^–4S.m² mol^–1 respectively.

$λ_{m}^{0}$ Ba(OH)₂ in s.m² mol^–1 is

Easy

Solution

$\lambda _{M\left( {Ba{{\left( {OH} \right)}_2}} \right)}^o = \lambda _{M\left( {BaC{l_2}} \right)}^o + 2\lambda _{M\left( {NaOH} \right)}^o - 2\lambda _{M\left( {NaCl} \right)}^o$

$= {10^{ - 4}}\left( {280 + 2\left( {248} \right) - 2\left( {126} \right)} \right) = 524 \times {10^{ - 4}}$

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