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Q.

At 250C, 1 mole of butane is heated to form CO2 and H2O liquid. The work done for the given process is

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a

75.6 L atm

b

85.6 L atm

c

50.3 L atm

d

90.6 L atm

answer is B.

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Detailed Solution

W = P∆V = ∆ngRTC4H10(g) + 6.5 O2(g) →4CO2(g) + 5H2O(l)∆ng = 4 - 7.5 = - 3.5W = - 3.5 ×0.0821×298 = 85.6 L atm
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