The (C – H) bond length order in hydro-carbons in which the hybridisation of carbon is sp3 or sp2 or sp
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a
sp – s > sp2 – s > sp3 – s
b
sp – s > sp2 – s < sp3 – s
c
sp3 – s > sp2 – s > sp – s
d
sp3 – s > sp – s > sp2 – s
answer is C.
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Detailed Solution
As the % of s-character increases, closeness of electron cloud towards the nucleus increases, hence electronegativity of the hybridised orbital increases, therefore size of the hybrid orbital decreases and hence C — H bond length decreases. (or)