Q.

Cr2O7−2+NO2−+H+→Cr+3+NO3−+H2O . If the above reaction is balanced, the number of H+ ions involved are

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a

8

b

6

c

4

d

9

answer is A.

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Detailed Solution

6e−+14H++Cr2O7−2→2Cr+3+7H2O [H2O+NO2−→NO3−+2H++2e−]×3 No. of H+ ions involved=14–6=8
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Cr2O7−2+NO2−+H+→Cr+3+NO3−+H2O . If the above reaction is balanced, the number of H+ ions involved are