First slide

Relation between Delta H and Delta U

Question

At $27^{0} c$ for the reaction, ${CaCO}_{3} (s) ⇌ CaO (s) + {CO}_{2} (g), ∆ H - ∆ E will be$

Easy

Solution

$∆ H - ∆ E = ∆ n_{g} RT; ∆ n_{g} = 1 - 0 = 1; T = 300 K ∆ H - ∆ E = 300 R$

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