At 400C , the vapour pressure in torr of methanol and ethanol solution is P=119x+135 where x is the mole fraction of methanol. Hence, correct statement is/are

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vapour pressure of pure methanol is 119 torr

vapour pressure of pure ethanol is 135 torr

vapour pressure of equimolar mixture of each is 127 torr

mixture is completely immiscible

answer is B.

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Detailed Solution

P=119x+135 P=PA0x+PB0(1−x) P=PA0x+PB0−PB0x P=PB0+(PA0−PB0)x PB0=135 ; PA0−PB0=119

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