First slide

Hardness of water

Question

$Ca {(OH)}_{2} \to_{excess}^{{CO}_{2}} A .$ Correct statement about ‘A’ is

Easy

A

It is responsible for temporary hardness of water
B

It is insoluble in water
C

On strong heating ‘A’ forms a metal carbonate
D

All are correct

Solution

$' A' is Ca {({HCO}_{3})}_{2}$
It is soluble in water, responsible for temporary hardness of water.
$Ca {({HCO}_{3})}_{2} \overset{Δ}{\to} {CaCO}_{3} + H_{2} O + {CO}_{2}$
${CaCO}_{3} \overset{Δ}{\to} CaO + {CO}_{2}$
$Ca {({HCO}_{3})}_{2} \overset{Strong ∆}{\to} CaO + H_{2} O + 2 {CO}_{2}$

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