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Q.

The CaCO3 is heated in a closed vessel of volume 1 litre of 600 K to form CaO and CO2. The minimum weight of CaCO3 required to establish the equilibriumCaCO3(s)→CaO(s)+CO2(g) is Kp=2.50atm

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answer is 5.

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Detailed Solution

KP=PCO2=2.5atm No. Of moles of CO2 = No. Of moles of CaCO3 required = n = PVRT = 2.5 x 10.082 x 600n = 0.0508 mass of CaCO3 = 0.0508 x 100 = 5.08g

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