For CaCO3(s)⇌ΔCaO(s)+CO2(g), the equilibrium constant KC and Kp for the thermal decomposition of calcium carbonate is
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a
KC=CO2(g);Kp=pCO2
b
KC=CaCO3(s);Kp=pCaCO3
c
KC=[CaO(s)];Kp=pCaO
d
KC=CO2(g);Kp=pCaO
answer is A.
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Detailed Solution
For heterogeneous chemical equilibrium,CaCO3(s)⇌ΔCaO(s)+CO2(g)On the basis of the stoichiometric equation, we can write,KC=[CaO(s)]CO2(g)CaCO3(s) Since, CaCO3(s) and [CaO(s)] are both constant, therefore modified equilibrium constant for the thermal decomposition of calcium carbonate will beKC=CO2(g) or Kp=pCO2