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Q.

For CaCO3(s)⇌ΔCaO(s)+CO2(g), the equilibrium constant KC and Kp for the thermal decomposition of calcium carbonate is

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a

KC=CO2(g);Kp=pCO2

b

KC=CaCO3(s);Kp=pCaCO3

c

KC=[CaO(s)];Kp=pCaO

d

KC=CO2(g);Kp=pCaO

answer is A.

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Detailed Solution

For heterogeneous chemical equilibrium,CaCO3(s)⇌ΔCaO(s)+CO2(g)On the basis of the stoichiometric equation, we can write,KC=[CaO(s)]CO2(g)CaCO3(s) Since, CaCO3(s) and [CaO(s)] are both constant, therefore modified equilibrium constant for the thermal decomposition of calcium carbonate will beKC=CO2(g) or Kp=pCO2
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