First slide

Faraday's Laws

Question

Cadmium amalgam is prepared by electrolysis of a solution of CdCl₂, using a mercury cathode. How long should a current of 4 A be passed in order to prepare 10% by wt. Cd in Cd-Hg amalgam on cathode of 4.5 g Hg? (atomic wt. of Cd : 112)

Easy

A

400 sec
B

215.40 sec
C

861.6 sec
D

430.8 sec

Solution

10 g Cd should Present with 90 g H8.
wt. of Cd required with 4.5 g of Hg at cathode
$= \frac{10}{90} \times 4 .5 \Rightarrow 0 .5; ({Cd}^{2} + 2 e^{-} \to Cd) \begin{array}{ll} ∴ & \frac{0 .5}{112} \times 2 = \frac{4 \times t}{96500} \\ \Rightarrow & t = 215 .40 \sec \end{array}$

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