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Calculate the amount of heat evolved during the complete combustion of 100 ml of liquid benzene from the following data:(i) 18 g graphite on complete combustion evolves 590 kJ of heat(ii) 15889 kJ of heat is required to dissociate all the molecules of 1 liter water into H, and Or.(iii) The heat of formation of liquid benzene is +50 kJ/mol.(iv) Density of C6H6(l) = 0.87 g ml-1

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answer is 3645 KJ..

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Detailed Solution

C(s)+O2(g)→CO2(g)ΔHf∘CO2=59018/12kJ/mol=393.33kJ/molH2(g)+1/2O2(g)→H2O(l)ΔHf∘H2O(1)=−158891000/18=−286kJmol−1C6H6(l)+7.5O2(g)→6CO2(g)+3H2O(l)ΔHcomb ∘=6×(−393.33)+3(−286)−50=−2359.98−858−50≅−3268kJ/mol. Heat evolved =3268×100×0.8778kJ=3645kJ.

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Calculate the amount of heat evolved during the complete combustion of 100 ml of liquid benzene from the following data:(i) 18 g graphite on complete combustion evolves 590 kJ of heat(ii) 15889 kJ of heat is required to dissociate all the molecules of 1 liter water into H, and Or.(iii) The heat of formation of liquid benzene is +50 kJ/mol.(iv) Density of C6H6(l) = 0.87 g ml-1