Calculate the amount of Ni needed in the Mond's process given belowNi+4CO  →    NiCO4If CO used in this process is obtained through a process, in which 6 g of carbon in mixed with 44 g CO2.

C           +            CO2       →      2CO given moles: 612     4444                    =0.5     =1So C is limiting reagent∴    CO formed = 1 moleNow moles of Ni need to react with 1 mole of CO = 14                   mass of ‘Ni’  =  14  ×  58.7  =  14.675 g