Calculate the conductivity of 0.2 mol L-1 KCI solution.

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

0.248 S cm−1

0.248 S m−1

2.48 S cm−1

2.48 S m−1

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

The cell constant is given by the equation: Cell constant, G∗= conductivity × resistance =1.29S/m×100Ω =129m−1=1.29cm−1Conductivity of 0.2 mol L-1 KCI solution cell constant/ resistance =G∗R=129m−1520Ω=0.248Sm−1

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

Get Expert Academic Guidance – Connect with a Counselor Today!

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET