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Calculate the conductivity of 0.2 mol L-1 KCI solution.
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a
0.248 S cm−1
b
0.248 S m−1
c
2.48 S cm−1
d
2.48 S m−1
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Correct option is B
The cell constant is given by the equation: Cell constant, G∗= conductivity × resistance =1.29S/m×100Ω =129m−1=1.29cm−1Conductivity of 0.2 mol L-1 KCI solution cell constant/ resistance =G∗R=129m−1520Ω=0.248Sm−1Similar Questions
Calculate the molar conductivity of 0.2 mol L-1 KCl solution.
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