Calculate the EMF of the cell Na/Na+1M//Mg+21M/Mg ; Given ENa/Na+0=+2.71 V and EMg+2/Mg0=-2.37 V ;
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a
+5.08 V
b
-5.08 V
c
-0.34 V
d
+0.34 V
answer is D.
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Detailed Solution
SOP of Sodium electrode is given, change it to SRP. ENa+/Na0=-2.71 V and EMg+2/Mg0=-2.37 V; Both are SRP values;From the cell notation ,Sodium electrode( LHE ) is the Anode,Magnesium electrode ( RHE ) is the Cathode,Ecell° =ECathode°-EAnode°=-2.37 V-(-2.71) V =+0.34 V