Q.
Calculate the energy required for the process He+(g)→He2+(g)+e-. The ionization energy for the H-atom in the ground state is 2.18×10-18 J atom -1
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a
8.72×10-18 atoms -1
b
10.75×10-20 atoms -1
c
12.77×10-22 atoms -1
d
15.22×10-15 atoms -1
answer is A.
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Detailed Solution
Energy of electron in unielectron atomic system,En=-2π2mZ2e4n2h2For H-atom, ionisation energy (IE) = E∞-E1IE=0--2π2me41212h2 (where, Z=1 and n=1 for H-atom)IE=2.18×10-18 J atom -1 For He+,IE=E∞-E1=0--2π2me42212h2=4×2π2me4h2=4×2.18×10-18 J atom -1=8.72×10-18 J atom -1∴ The energy required for the process He+⟶He2++e-is 8.72×10-18 atoms -1.
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