Q.

Calculate the equilibrium constant for the reaction,    Zn(s)+Cu2+(aq)⟶Zn2+(aq)+Cu(s)                                                           Given, Ecell ∘=1.1V

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a

2×1032

b

2×1034

c

2×1037

d

2×1039

answer is C.

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Detailed Solution

Zn(s)+Cu2+(aq)⟶Zn2+(aq)+Cu(s)0=Ecell=Ecell∘−2.303RT2Flog⁡Zn2+Cu2+or     Ecell∘=2.303RT2Flog⁡Zn2+Cu2+But at equilibrium Zn2+Cu2+=KC               Ecell ∘=0.059V2log⁡KC=1.1Vlog⁡KC=1.1V×20.059V=37.288        KC=2×1037 at 298K
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