Calculate the equivalent weight of Ca(OH)2 in the following reaction.Ca(OH)2+H2SO4⟶CaSO4+2H2O (at. wt., Ca=40,O=16,H=1 ) .

Mol. wt. of  Ca(OH)2=40+2(16+1)                                 =74 g mol−Reaction.Ca(OH)2+H2SO4⟶CaSO4+2H2O1 molecule                   no OH-group= 2 OH- groups.∴  No. of OH-groups replaced from one molecule of Ca(OH)2=2−0=2∴ Eq.wt.of Ca(OH)2= Mol. wt. of Ca(OH)2 no. of OH− groups replaced  from one molecule of Ca(OH)2=742=37