Q.
Calculate the equivalent weight of KOH with the help of following reaction.2KOH+H2SO4⟶K2SO4+2H2O (at. wt., K=39,O=16,H=1 ).
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answer is 56.
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Detailed Solution
Mol. wt. of KOH=39+16+1=56gmol−Reaction.2KOH + H2SO4⟶ K2SO4 + 2H2O 2molecules 2H+ions no H+-ion 22=1 molecule 22=1H+ion ∴ no. of H+ions that react with one molecule of KOH=1-0=1∴ Eq. wt. of KOH= Mol. wt. of KOH no. of H+ions that react with one molecule of KOH =561=56 Ans.