Q.

Calculate the equivalent weight of KOH with the help of following reaction.2KOH+H2SO4⟶K2SO4+2H2O (at. wt., K=39,O=16,H=1 ).

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answer is 56.

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Detailed Solution

Mol. wt.  of KOH=39+16+1=56gmol−Reaction.2KOH         +       H2SO4⟶       K2SO4    +    2H2O 2molecules            2H+ions            no H+-ion 22=1  molecule     22=1H+ion ∴ no. of H+ions  that react with one molecule of KOH=1-0=1∴ Eq. wt. of KOH= Mol. wt. of KOH no. of H+ions that react                                  with one molecule of KOH                             =561=56 Ans.
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Calculate the equivalent weight of KOH with the help of following reaction.2KOH+H2SO4⟶K2SO4+2H2O (at. wt., K=39,O=16,H=1 ).