Calculate the equivalent weight of potassium chlorate in the reaction :KClO3⟶KCl+3O (at. wt., K=39,Cl=35.5,O=16 )

KClO3⟶KCl+3O39+35.5+(3×16)6×12O=122.5 Eq. wt. of KClO3= Mol. wt. of KClO3 no. of 12O atoms formed  in molecule of KClO3=39+35.5+(3×16)6=122.56=20.42 Ans.