Calculate the heat of formation of KOH from the following data in K.Cal. K(s) + H2O + aq → KOH(aq)+1/2 H2; ΔH = -48.4K.Cal H2(g) + 1/2O2(g) → H2O(l); ΔH = -68.44K.Cal KOH(s) + aq → KOH(aq) ; ΔH = -14.01K.Cal
Moderate
Solution
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