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Q.

Calculate the limiting molar conductivity of NaCl and KBr from the above table

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a

NaCl -126.4KBr  -150.6

b

NaCl -126.4KBr  -151.6

c

NaCl -150.6KBr  -126.4

d

NaCl -151.6KBr  -126.4

answer is B.

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Detailed Solution

ΛNaCl∘=50.1+76.3=126.4S cm2mol−1ΛKBr∘=73.5+78.1=151.6S cm2mol−1
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