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Calculate the limiting molar conductivity of NaCl and KBr from the above table
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a
NaCl -126.4KBr -150.6
b
NaCl -126.4KBr -151.6
c
NaCl -150.6KBr -126.4
d
NaCl -151.6KBr -126.4
answer is B.
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Detailed Solution
ΛNaCl∘=50.1+76.3=126.4S cm2mol−1ΛKBr∘=73.5+78.1=151.6S cm2mol−1
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