Calculate the limiting molar conductivity of NaCl and KBr from the above table
NaCl -126.4KBr -150.6
NaCl -126.4KBr -151.6
NaCl -150.6KBr -126.4
NaCl -151.6KBr -126.4
ΛNaCl∘=50.1+76.3=126.4S cm2mol−1ΛKBr∘=73.5+78.1=151.6S cm2mol−1