Calculate the mass of anhydrous oxalic acid, which can be oxidised to CO2(g) by 100 mL of an MnO4− solution, 10mL of which is capable of oxidising 50 mI of 1N oxalic acid.
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a
45 g
b
22.5 g
c
30 g
d
12.25 g
answer is B.
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Detailed Solution
Let normality of KMnO4 solution is N∴N×10=50×1 ⇒ N=5m-eq, of MnO4− = m-eq. of oxalic acid=N1V1=WE×10005×100=W(90/2)×1000⇒W=22.5g