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Q.

Calculate the millimoles of SeO32- in solution on the basis of following data:70 ml of M60 solution of KBrO3 was added to SeO32- solution. The bromine evolved was removed by boiling and excess of KBrO3 was back titrated with 12.5 mL M25 solution of NaAsO2.The reactions for the above data is/are given below. (1) SeO32-+BrO3-+H+→SeO42-+Br2+H2O (2) BrO3-+AsO2-+H2O→Br-+AsO43-+H+

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a

1.6×10-3

b

1.25

c

2.5×10-3

d

zero

answer is C.

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Detailed Solution

(a) SeO3-2+4+BrO3-+5+H+→SeO4+2+6+Br20+H2O (b) BrO3-+5+AsO2-+3+H2O→Br--1+AsO43-+5+H+In reaction (2)gm . eq. of BrO3-=gm . eq. of AsO2-nBrO3×6=nAsO2×2=12.51000×125×2=10-3nBrO3=10-36In reaction (1) moles of BrO3-consumed =701000×160-10-36=10-3gm eq. of SeO32-=gm . eq. of BrO3-nSeO32-×2=10-3×5;nSeO32-=2.5×10-3

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