Calculate the minimum uncertainty in velocity of a particle of mass 1.1 × 10−27 kg if uncertainty in its position is 3 × 10−10 cm.

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1.5 × 10−4 m

2.5 × 10−4 m

3.5 × 10−4 m

4.5 × 10−4 m

answer is A.

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Detailed Solution

Δx. Δv ≥ h4πmΔv ≥ hΔx.4π.m=6.6 × 10−343 × 10−10 × 10−2m × 4 × 3.14 ×1.1 × 10−27= 1.5 × 10−4 m/s

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