Calculate the molality of 1 L solution of 80% H2SO4. (w/V), given that the density of the solution is 1.80 g mL-1.

WH2SO4 =800 c in 10oo mLvolume of solution = 1000 mLWeight of solution = 1000.0 x 1.80= 1800 gweight of water =1800 - 800 =1000 gMolality =800×100098×1000=8.16mol kg−1