Calculate the molality of 1 litre solution of 93% H2SO4 (weight/volume). The density of the solution is 1.84 g/mL.

Mass of H2SO4 in 100ml of 93% H2SO4solution = 93g∴ Mass of H2SO4 in 1000 ml of the H2SO4 solution = 930gMass of 1000 ml H2SO4 solution = 1000 × 1.84 = 1840gMass of water in 1000 ml of solution = 1840 – 930 = 910 g Moles of H2SO4=Wt . of H2SO4 Mol Wt . of H2SO4=93098∴Moles of H2SO4 in 1 kg of water =93098×1000910=10.43 mol kg-1∴Molality of 1 litre solution = 10.43