Calculate molality of 1 litre solution of 93% (w/v) H2SO4 (The density of solution is 1.84 g/ml)

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

9.42

10.42

11.42

12.42

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Given H2SO4 is 93% by volume weight of H2SO4=93gvolume of solution = 100 mldensity of the solution=1.84 g∴ Weight of solution =100×1.84g=184gweight of water = 184 - 93 = 91 g Molality =Moleswt. of water in kg =93×100098×91=10.42m

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

Get Expert Academic Guidance – Connect with a Counselor Today!

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET