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Q.

Calculate molality of 1  litre solution of 93% (w/v) H2SO4 (The density of solution is 1.84 g/ml)

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a

9.42

b

10.42

c

11.42

d

12.42

answer is B.

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Detailed Solution

Given H2SO4 is 93% by volume weight of H2SO4=93gvolume of solution = 100 mldensity of the solution=1.84 g∴ Weight of solution =100×1.84g=184gweight of water = 184 - 93 = 91 g Molality =Moleswt. of water in kg                =93×100098×91=10.42m
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