Calculate the molar conductivity of 0.2 mol L-1 KCl solution.

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124×10−2Sm2mol−1

124×10−3S m2 mol−1

124×10−4S m2mol−1

124×10−5S m2mol−1

answer is D.

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Detailed Solution

Concentration =0.2mol L−1 =1000×0.2 mol m−3=200 mol m−3 Molar conductivity =Λm=κC =248×10−3Sm−1200molm−3 =124×10−5Sm2mol−1

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