Calculate the molar conductivity of 0.2 mol L-1 KCl solution.
124×10−2Sm2mol−1
124×10−3S m2 mol−1
124×10−4S m2mol−1
124×10−5S m2mol−1
Concentration =0.2mol L−1 =1000×0.2 mol m−3=200 mol m−3 Molar conductivity =Λm=κC =248×10−3Sm−1200molm−3 =124×10−5Sm2mol−1