Calculate the molarity and normality of a solution containing 0.5 g of NaOH dissolved in 500 ml. solution-

Weight  of NaOH dissolved = 0.5 gVolume  of NaOH Solution = 500 ml Calculation of molarity 0.5 g of NaOH =0.540 moles of NaOH[∵ Mol. wt. of NaOH = 40]                        = 0.0125 mole Thus 500 ml of the solution contain NaOH = 0.0125 mole∴ 1000 ml of the solution contain =0.0125500×1000=0.025MHence molarity of the solution = 0.025 MCalculation of normalitySince NaOH is monoacidic; Eq. wt. of NaOH = Mol. wt. of NaOH = 40 ∴ 0.5 g of NaOH=0.540 g equivalents = 0.0125 gram equivalents Thus 500 ml of the solution contain NaOH = 0.0125 g equiv. ∴ 1000 ml of the solution contain=0.0125500×1000=0.025Hence normality of the solution = 0.025 N