Calculate the mole fraction of CH3OH in a solution that is prepared by adding 50 grams of CH3OH to 100 grams of water ?

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0.629

0.781

0.127

0.219

answer is D.

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Detailed Solution

WCH3OH=50 g WH2O =100 g nH2O =10018=5.55 nCH3OH=5032=1.56 ntotal=5.55+1.56=7.11 XCH3OH=1.567.11=0.219 XH2O=1-0.219=0.781

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