Calculate the mole fraction of ethylene glycol (C2H6O2) in a solution containing 20% of C2H6O2 by mass.

Assume that we have 100 g of solution (because percentage composition). Solution will contain 20 g of ethylene glycol and 80 g of water.Molar mass of C2H6O2 = 12 x 2 + 6 x 1 + 16 x 2                                     = 62 g mol-1 Moles of C2H6O2=2062=0.322mol Moles of water =80g18gmol−1=4.444molχglycol = moles of C2H6O2 moles of C2H6O2+ moles of H2O          =0.322mol0.322mol+4.444mol=0.068