Calculate the normal boiling point of a sample of sea water found to contain 3.5% of NaCl and 0.13% of MgCl2 by mass. The normal boiling point of water is 100oC and Kb (water) = 0.51 K kg mol-1. Assume that both the salts are completely ionised

Mass of NaCl = 3.5 gNumber of moles of NaCl=3.558.5Number of ions furnished by one molecule of NaCl is 2. So, actual number of moles of particles furnished by sodium chloride =2×3.558.5Similarly, actual number of moles of particles furnished by magnesium chloride =3×0.1395Total number of moles of particles =(2×3.558.5+3×0.1395)=0.1238Mass of water =(100−3.5−0.13)=96.37 g=96.371000 kgMolality =0.123896.37×1000=1.2846ΔTb=Molality ×Kb=1.2846×0.51=0.655 KHence, boiling point of sea water = 373.655 K or 100.655oC