Q.

Calculate normality of the mixture obtained by mixing 100 ml of 0.1 N HCl and 50 ml of 0.25 N NaOH solution.

see full answer

Want to Fund your own JEE / NEET / Foundation preparation ??

Take the SCORE scholarship exam from home and compete for scholarships worth ₹1 crore!*

An Intiative by Sri Chaitanya

0.0467 N

0.0367 N

0.0267 N

0.0167 N

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Meq. of HCl =100×0.1=10Meq. of NaOH =50×0.25=12.5∴ HCl and NaOH neutralize each other with equal equilents. Meq. of NaOH left = 12.5 - 10 = 2.5Volume of new solution = 100 + 50 = 150 ml.NNaOH left =2.5150=0.0167NHence normality of the mixture obtained is 0.0167 N

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET