Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

Calculate the percent dissociation of H2S(g) if 0.1 mole of H2S is kept in 0.4 lit vessel at 1000 K for the reaction 2H2S(g)⇌2H2(g)+S2(g) . Value of kc is 1.0×10−6

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

2

b

1

c

0.1

d

0.2

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

2H2S(g)⇌2H2(g)+S2(g)                 Molar conc. at equilibrium =0.1−x0.4   x0.4   x0.8 Kc=[H2]2[S2][H2S]2⇒x=2×10−3 %x=2×10−30.1×100=2
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring