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Q.

Calculate the percentage degree of  dissociation of an electrolyte XY2 (Normal molar mass =164) in water. If the observed molar mass by measuring elevation in boiling point is 65.6

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a

75%

b

25%

c

65%

d

37.5 %

answer is A.

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Detailed Solution

AB2→ A+2Bi = Vant Hoff factor = 1 + 2d (d = degree of dissociation)i=Normal   massObserved  mass=16465.6=2.5⇒1+2d=2.5⇒d=0.75, Thus percentage dissociation = 0.75 × 100 = 75%
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