Calculate pH of 0.10 N acetic acid having Ka=1.8×10-5
2.8
5.6
6.8
3.4
CH3COOH⇌CH3COO-+H+(weak acid)
Initially l 0 0
At equil. (1-α) α α
[H+]=Cα or C·KaC=KaC
=1.8×10-5×0.1=1.34×10-3M
pH=-log H+=-log1.34×10-3=2.87