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Calculate pH of 0.002 N   NH4OH having  2%  dissociation

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a
7.6
b
8.6
c
9.6
d
10.6

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detailed solution

Correct option is C

NH4OH is a weak base and partially dissociated                                  NH4OH  ⇌  NH4+ + OH-Concentration              1                    0            0before dissociationConcentration            1-α                α          αafter dissociationC=2×10-3  ; α=2100    ∴   OH- = Cα = 2 × 10-3 × 2100 = 4 × 10-5 MpOH = -log OH-        = -log 4 × 10-5 = 4.4 pH=14-4.4 = 9.6

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