Calculate pH of $$0.002$$ N $$NH4OH$$ having $$2$$% dissociation

Question

Calculate pH of $$0.002$$ N   $$NH4OH$$ having  $$2$$%  dissociation

Infinity Learn · Accepted Answer

$$NH4OH$$ is a weak base and partially dissociated                                  $$NH4OH$$  ⇌  $$NH4+$$ $$+$$ $$OH-Concentration$$              $$1$$                    $$0$$            $$0before$$ dissociationConcentration            $$1-$$α                α          αafter $$dissociationC=2$$×$$10-3$$  ; α$$=2100$$    ∴   $$OH-$$ $$=$$ Cα $$=$$ $$2$$ × $$10-3$$ × $$2100$$ $$=$$ $$4$$ × $$10-5$$ MpOH $$=$$ $$-log$$ $$OH-$$        $$=$$ $$-log$$ $$4$$ × $$10-5$$ $$=$$ $$4.4$$ $$pH=14-4.4$$ $$=$$ $$9.6$$

Calculate pH of 0.002 N ${NH}_{4} OH$ having 2% dissociation

Unlock the full solution & master the concept.

Ready to Test Your Skills?

free study material

Calculate pH of 0.002 N NH4OH having 2% dissociation

Unlock the full solution & master the concept.

Ready to Test Your Skills?

free study material

Calculate pH of 0.002 N ${NH}_{4} OH$ having 2% dissociation