Q.
Calculate pH of a solution of given mixture (0.1 mole CH3COOH + 0.2 mole CH3COONa) in 100 ml of mixture. K = 2 × 10-5.
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a
5.0
b
5.6
c
6.6
d
7.6
answer is A.
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Detailed Solution
We havePH = - log Ka + log SaltAcid = - log( 2 × 10-5) + log( 0.2/0.1) =4.6990+0.3010 =5
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