Calculate pH of a solution of given mixture (0.1 mole CH3COOH + 0.2 mole CH3COONa) in 100 ml of mixture. K = 2 × 10-5.
5.0
5.6
6.6
7.6
We have
PH = - log Ka + log SaltAcid = - log( 2 × 10-5) + log( 0.2/0.1) =4.6990+0.3010 =5