Calculate pH of solution whose 100 ml contains 0.2 g NaOH dissolved in it.

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10.699

11.699

12.699

13.699

answer is C.

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Detailed Solution

100 ml solution of NaOH solution= 0.2 g NaOH∴ 1000 ml solution of NaOH contains = 2 g NaOHNormality of solution = 240 = 0.05 N=[OH-]∴ H+ = 10-140.05=15×10-12=2×10-13PH=-log(2×10-13) =13-log 2 =12.699

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