Q.

Calculate pH of solution whose 100 ml contains 0.2 g NaOH dissolved in it.

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a

10.699

b

11.699

c

12.699

d

13.699

answer is C.

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Detailed Solution

100 ml solution of NaOH solution= 0.2 g NaOH∴  1000 ml solution of NaOH contains = 2 g NaOHNormality of solution = 240 = 0.05 N=[OH-]∴    H+ = 10-140.05=15×10-12=2×10-13PH=-log(2×10-13)     =13-log 2      =12.699
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