Q.

Calculate the quantity of sodium carbonate (anhydrous) required to prepare 250 ml 0.1M solution.

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a

2.65 grams

b

4.95 grams

c

6.25 grams

d

None of these

answer is A.

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Detailed Solution

We know that Molarity =WM×Vwhere; W = Mass of Na2CO3 in gram M = Molecular mass of Na2CO3 in grams = 106V = Volume of solution in litres                   =2501000=0.25Molarity =110Hence, =110=W106×0.25or W=106×0.2510=2.65 grams
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