Calculate the root mean square velocity of nitrogen at 100°C ( i) using the concept of Boltzmann constant, k⋅k=1.381×10−23JK
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answer is 576.6.
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Detailed Solution
Urms=3kTm1/2 where k=1.381×10−23JK−T=100+273=373K,m= mol. wt. of N2×1.66×10−27kg=(2×14)×1.66×10−27kg=28×1.66×10−27kgUrms=3×1.381×10−23kgm2s−2K−×373K28×1.66×10−27kg1/2∵J=kgm2s−2g=332474m2s−21/2=576.6ms− Ans. Second methodUrus=3RTM1/2=3×8.314×107ergmol−K−×373K28gmol−1/2=3322630714gcm2s−21/2=57642cms−=57642cms−×1m100cm=576.42ms−