Calculate the solubility of silver phosphate (Ag3PO4) in 0.1M AgNO3 (kSP Ag3PO4= 1.1 X 10-16)

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1 x 10-8 M

1 x 10-15 M

1.1 x 10-15 M

1.1 x 10-13 M

answer is D.

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Detailed Solution

Ag3PO4⇌Ag+(3s+0.1)+PO4−3Ksp=(3s+0.1)3(s)=1.1×10−1610−3×s=1.1×10−16s=1.1×10−13

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