Calculate the volume(ml) of H2 gas at 25°C and 1.2 bar that will be released from the action of 0.2 g aluminium (present in drainex) on sodium hydroxide solution. (at. wt., Al= 27).

2Al+2NaOH+2H2O    ⟶2NaAlO2+3H22×27=54g                           3×22.4L=67.2L54gAl produce H2    =67.2L0.2gAl produce H2    =67.2L54g×0.2g=0.249LP1=1.0bar=1.0atm;P2=1.2bar=1.2atmV1=0.249L;V2=?;T1=273K;T2=25+273=298KP1V1T1=P2V2T2(gas equation)∴  V2=P1V1T1×T2P2=1atm×0.249L273K×298K1.2atm=0.2265Lor V2=0.2265L×1000mL1L= 226.5ml